A non-stoichiometric compound Cu 1.8 S is formed due to the incorporation of Cu 2+ ions in the lattice. What is the mole percentage of Cu 2+ present in the compound?

Question

A non-stoichiometric compound Cu 1.8 S is formed due to the incorporation of Cu 2+ ions in the lattice. What is the mole percentage of Cu 2+ present in the compound?, 88.88, 89.8, 63.5%, 11.11

MARKS App · Accepted Answer

In one mole, Let there be Cu +2 =x moles ∴ Cu + = 1.8 − x moles ∵ 2 x + 1.8 − x 1 = + 2 x = 0.2 % Cu + 2 = 0.2 1.8 × 100 = 11.11 %

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