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A normal woman, whose father was colour-blind is married to a normal man. The sons would be:
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$50 \%$ colour-blind
The genotype of normal woman with colourblind father $=\mathrm{XX}^{\mathrm{h}}$
The genotype of normal $\operatorname{man}=X Y$
$\therefore 50 \%$ of the sons would be colourblind.
The genotype of normal $\operatorname{man}=X Y$
$\therefore 50 \%$ of the sons would be colourblind.
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