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A nuclear reaction given by ${ }_z \mathrm{X}^{\mathrm{A}} \rightarrow{ }_{z+1} \mathrm{Y}^{\mathrm{A}}+-1^{e^0}+\bar{v}$ represents:
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The correct answer is:
$\beta$-decay
Emission of electron \(\left(\mathrm{e}^{-}\right)+\)antineutrino \(\left(\gamma^{-}\right)\)
\(\Rightarrow \beta\)-decay.
\(\Rightarrow \beta\)-decay.
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