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A nuclear transformation is denoted by $X(n, \alpha){ }_3^7 \mathrm{Li}$. Which of the following is the nucleus of element $X$ ?
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The correct answer is:
${ }_5^{10} \mathrm{~B}$
${ }_5^{10} \mathrm{~B}$
$\mathrm{X}+{ }_0^1 \mathrm{n} \rightarrow{ }_2^4 \mathrm{He}+{ }_3^7 \mathrm{Li}$
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