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A nucleus disintegrates into two nuclear parts which have their velocities in the ratio $2: 1$. The ratio of their nuclear sizes will be
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The correct answer is:
$1: 3^{1 / 2}$
$1: 3^{1 / 2}$
$\frac{R_1}{R_2}=\left(\frac{m_2}{2 m_2}\right)^{1 / 3}$
$\Rightarrow \frac{R_1}{R_2}=1: 2^{1 / 3}$
$\Rightarrow \frac{R_1}{R_2}=1: 2^{1 / 3}$
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