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A nucleus has mass number $A_1$ and volume $V_1$. Another nucleus has mass number $A_2$ and volume $V_2$. If the relation the mass numbers is $\mathrm{A}_2=3 \mathrm{~A}_1$, then $\frac{\mathrm{V}_1}{\mathrm{~V}_2}=$
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Verified Answer
The correct answer is:
$\frac{1}{3}$
We have
$\begin{aligned} & \mathrm{V} \propto \mathrm{A} \\ & \frac{\mathrm{V}_1}{\mathrm{~V}_2}=\frac{\mathrm{A}_1}{\mathrm{~A}_2}=\frac{1}{3}\end{aligned}$
$\begin{aligned} & \mathrm{V} \propto \mathrm{A} \\ & \frac{\mathrm{V}_1}{\mathrm{~V}_2}=\frac{\mathrm{A}_1}{\mathrm{~A}_2}=\frac{1}{3}\end{aligned}$
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