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A nucleus ${ }_n^m X$ emits one $\alpha$-particle and two $\beta^{-}$particles. The resulting nucleus is
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The correct answer is:
${ }_n^{m-4} X$
${ }_n^m X \stackrel{\alpha}{\rightarrow}{ }_{n-2} X^{m-4} \stackrel{2 \beta}{\rightarrow}{ }_n X^{m-4}$
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