The decrease in mass $\mathrm{\Delta }m$ will appear as the kinetic energy of the two daughter nuclei. Since the two nuclei formed are of equal masses, they will share the available energy equally among themselves. If $v$ is the speed of a daughter nucleus, then $\frac{1}{2}\left(\frac{M}{2}\right)v^2=\frac{1}{2}\mathrm{\Delta }m{c}^2$

or $v=\mathrm{ }c\sqrt{\frac{2\mathrm{\Delta }m}{M}}$