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A number of Carnot engines are operated at identical cold reservoir temperatures $\left(T_{L}\right)$. However, their hot reservoir temperatures are kept different. A graph of the efficiency of the engines versus hot reservoir temperature $\left(T_{H}\right)$ is plotted. The correct graphical representation is
Options:
- A
- B
- C
- D
Solution:
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Verified Answer
The correct answer is:
Efficiency of a Carnot's engine is given as
$\eta=1-\frac{T_{L}}{T_{H}}$
where, $T_{L}=$ temperature of cold reservoir and
$T_{H}=$ temperature of hot reservoir.
At constant $T_{L}$, we can say that, with the increase in the valuc of $T_{H}, \eta$ will also incrcasc.
So, the graph between efficiency and $T_{H}$ is correctly depicted in option (b).
$\eta=1-\frac{T_{L}}{T_{H}}$
where, $T_{L}=$ temperature of cold reservoir and
$T_{H}=$ temperature of hot reservoir.
At constant $T_{L}$, we can say that, with the increase in the valuc of $T_{H}, \eta$ will also incrcasc.
So, the graph between efficiency and $T_{H}$ is correctly depicted in option (b).
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