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A number of small water droplets of surface tension ' $T$ ', each of radius ' $r$ ' are combined to form a single drop of radius ' $R$ '. If the released energy is converted into kinetic energy, then the velocity acquired by the bigger drop is ____ ($\rho$ - density of water)
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The correct answer is:
$\sqrt{\frac{6 \mathrm{~T}}{\rho}\left(\frac{\mathrm{R}-\mathrm{r}}{\mathrm{rR}}\right)}$
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