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A organ pipe open on both ends in the $\mathrm{n}^{\text {th }}$ harmonic is in resonance with a source of 1000 Hz . The length of pipe is 16.6 cm and speed of sound in air is $332 \mathrm{~m} / \mathrm{s}$. Find the value of $n$.
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$1$
Given that, $\mathrm{f}=1000 \mathrm{~Hz}, \mathrm{v}=332 \mathrm{~m} / \mathrm{s}, \mathrm{l}=16.6 \mathrm{~cm}$$=16.6 \times 10^{-2} \mathrm{~m}$
Frequency in a organ pipe open on both ends,
$\mathrm{f}=\frac{\mathrm{nv}}{2 \mathrm{l}}$
or $\quad \mathrm{n}=\frac{2 \mathrm{fl}}{\mathrm{v}}$
or $\quad \mathrm{n}=\frac{2 \times 1000 \times 16.6 \times 10^{-2}}{332}=1$
Frequency in a organ pipe open on both ends,
$\mathrm{f}=\frac{\mathrm{nv}}{2 \mathrm{l}}$
or $\quad \mathrm{n}=\frac{2 \mathrm{fl}}{\mathrm{v}}$
or $\quad \mathrm{n}=\frac{2 \times 1000 \times 16.6 \times 10^{-2}}{332}=1$
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