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A pair of adjacent coils has a mutual inductance of $1.5$
$\mathrm{H}$. If the current in one coil changes from 0 to $20 \mathrm{~A}$ in $0.5 \mathrm{~s}$, what is the change of flux linkage with the other coil?
$\mathrm{H}$. If the current in one coil changes from 0 to $20 \mathrm{~A}$ in $0.5 \mathrm{~s}$, what is the change of flux linkage with the other coil?
Solution:
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Verified Answer
Given: Mutual inductance $\mathrm{M}=1.5 \mathrm{H}$
change in current $\mathrm{dI}=20-0=20 \mathrm{~A}$
change in time $\mathrm{dt}=0.5 \mathrm{~s}$
To find: change in flux $\mathrm{d} \phi=$ ?
Formula used: $\phi=$ MI
$$
\phi=\mathrm{MI} \Rightarrow \mathrm{d} \phi=\mathrm{MdI} \Rightarrow \mathrm{d} \phi=1.5 \times 20=30 \mathrm{~Wb}
$$
change in current $\mathrm{dI}=20-0=20 \mathrm{~A}$
change in time $\mathrm{dt}=0.5 \mathrm{~s}$
To find: change in flux $\mathrm{d} \phi=$ ?
Formula used: $\phi=$ MI
$$
\phi=\mathrm{MI} \Rightarrow \mathrm{d} \phi=\mathrm{MdI} \Rightarrow \mathrm{d} \phi=1.5 \times 20=30 \mathrm{~Wb}
$$
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