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A parachutist after bailing out falls $50 \mathrm{~m}$ without friction. When parachute opens, it decelerates at $2 \mathrm{~m} / \mathrm{s}^2$. He reaches the ground with a speed of $3 \mathrm{~m} / \mathrm{s}$. At what height, did he bail out?
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The correct answer is:
$293 \mathrm{~m}$
$293 \mathrm{~m}$
$s=50+\left(\frac{3^2-(2 \times 10 \times 50)}{2(-2)}\right)$
$=293 \mathrm{~m}$.
$=293 \mathrm{~m}$.
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