A parallel beam of light of wavelength 4000 A ∘ passes through a slit of width 5 × 10 - 3 m . The angular spread of the central maxima in the diffraction pattern is

Question

A parallel beam of light of wavelength 4000 A ∘ passes through a slit of width 5 × 10 - 3 m . The angular spread of the central maxima in the diffraction pattern is, 1.6 × 10 - 3 rad, 1.6 × 10 - 4 rad, 3.2 × 10 - 3 rad, 3.2 × 10 - 4 rad

MARKS App · Accepted Answer

Angular spread of the central maxima in the diffraction pattern = 2 λ e ( e = width of the slit) Here, e = 5 × 10 - 3 m , λ = 4000 Å Hence, 2 θ = 2 4000 × 10 - 10 5 × 10 - 3 = 1600 × 10 - 7 rad or 2 θ = 1.6 × 10 - 4 rad

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