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A parallel beam of monochromatic light of wavelength $5 \times 10^{-7} \mathrm{~m}$ is incident
normally on a single narrow slit of width $10^{-3} \mathrm{~mm}$. At what angle of diffraction,
the first minima is observed?
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normally on a single narrow slit of width $10^{-3} \mathrm{~mm}$. At what angle of diffraction,
the first minima is observed?
Solution:
2428 Upvotes
Verified Answer
The correct answer is:
$\sin ^{-1}\left(\frac{1}{2}\right)$
$\sin \theta=\frac{\lambda}{a}=\frac{5 \times 10^{-7} \mathrm{~m}}{10^{-6} \mathrm{~m}}=0.5=\frac{1}{2}$
$\therefore \theta=\sin ^{-1}\left(\frac{1}{2}\right)$
$\therefore \theta=\sin ^{-1}\left(\frac{1}{2}\right)$
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