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A parallel beam of monochromatic light of wavelength $600 \mathrm{~nm}$ passes through single slit of $0.4 \mathrm{~mm}$ width. Angular divergence corresponding to second order minima would be ______ $\times 10^{-3} \mathrm{rad}$.
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6
$\sin \theta \simeq \theta \simeq \frac{2 \lambda}{b}$
$=\frac{2 \times 600 \times 10^{-9}}{4 \times 10^{-4}}=3 \times 10^{-3} \mathrm{rad}$
Total divergence $=(3+3) \times 10^{-3}=6 \times 10^{-3} \mathrm{rad}$
$=\frac{2 \times 600 \times 10^{-9}}{4 \times 10^{-4}}=3 \times 10^{-3} \mathrm{rad}$
Total divergence $=(3+3) \times 10^{-3}=6 \times 10^{-3} \mathrm{rad}$
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