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A parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and area of each plate is $A$, the energy stored in the capacitor is
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Verified Answer
The correct answer is:
$\frac{1}{2} \varepsilon_0 E^2 A d$
Energy density for a parallel plate capacitor $=\frac{1}{2} \varepsilon_0 E^2$ and volume $=A d$
Total energy $=$ energy density $\times$ volume
$$
\begin{aligned}
& =\left(\frac{1}{2} \varepsilon_0 E^2\right) \times(A d) \\
& =\frac{1}{2} \varepsilon_0 E^2 A d
\end{aligned}
$$
Total energy $=$ energy density $\times$ volume
$$
\begin{aligned}
& =\left(\frac{1}{2} \varepsilon_0 E^2\right) \times(A d) \\
& =\frac{1}{2} \varepsilon_0 E^2 A d
\end{aligned}
$$
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