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A parallel plate capacitor is charged and then disconnected from the charging battery. If the plates are now moved further apart by pulling them by means of insulting handles, then
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the voltage across the capacitor increases
When the capacitor is charged and then disconnected, the charge across the plates remains a constant, even when the plates are separated.
The capacitance is related to the structure of parallel plate capacitor as $\frac{A \varepsilon_0}{d}$. When the plate is separated, the distance between the plate $d$ increases and hence the capacitance decreases.
Hence, according to the $Q=C V$ relation, the voltage across the capacitor increases in order to keep the charge constant.
The capacitance is related to the structure of parallel plate capacitor as $\frac{A \varepsilon_0}{d}$. When the plate is separated, the distance between the plate $d$ increases and hence the capacitance decreases.
Hence, according to the $Q=C V$ relation, the voltage across the capacitor increases in order to keep the charge constant.
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