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A parallel plate capacitor is made by stacking $n$ equally spaced plates connected alternately. If the capacitance between any two plates is $C$ then the resultant capacitance is
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$(n-1) C$
For \(n\) plates joined alternately, there will be \((n-1)\) capacitors connected in parallel Fig. Their
equivalent capacitance will be \(\mathrm{C}_{\mathrm{eq}}=(\mathrm{n}-1) \mathrm{C}\).
equivalent capacitance will be \(\mathrm{C}_{\mathrm{eq}}=(\mathrm{n}-1) \mathrm{C}\).
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