A particle A is projected from the ground with an initial velocity of 10 m s - 1 at an angle of 60 o with horizontal. From what height h should an another particle B be projected horizontally with velocity 5 m s - 1 so that both the particles collide in ground at point C if both are projected simultaneously? ( g = 10 m s - 2 )

Question

A particle A is projected from the ground with an initial velocity of 10 m s - 1 at an angle of 60 o with horizontal. From what height h should an another particle B be projected horizontally with velocity 5 m s - 1 so that both the particles collide in ground at point C if both are projected simultaneously? ( g = 10 m s - 2 ), 10 m, 30 m, 15 m, 25 m

MARKS App · Accepted Answer

For both the particle to collide at point, their time of fight should be same T = 2 usin θ g = 2 10 sin 60 10 = 2 3 2 time of fight of particle thrown from above t = 2h g equation we get, 2h g = 3 h = 15 m

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