A particle A suffers an oblique elastic collision with a particle B which is initially at rest. If their masses are same, then after the collision

Question

A particle A suffers an oblique elastic collision with a particle B which is initially at rest. If their masses are same, then after the collision, they will move in opposite directions, A continues to move in the original direction while B remains at rest, they will move in mutually perpendicular directions, A comes to rest and B starts moving in the direction of the original motion of A

MARKS App · Accepted Answer

as collision is elastic 1 2 mu 2 = 1 2 mv 1 2 + 1 2 v 2 2 u 2 = v 1 2 + v 2 2 ......... ( 1 ) Momentum is conserved m u → = m v → 1 + m v → 2 u → = v → 1 + v → 2 u 2 = v 1 2 + v 2 2 + 2 v 1 . v 2 cos ⁡ θ ....... ( 2 ) Solving ( 1 ) and ( 2 ) 2 v 1 . v 2 cos ⁡ θ = 0 cos ⁡ θ = 0 θ = 90 o i.e. v 1 & v 2 are mutually perpendicular.

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