A particle aimed at a target, projected with an angle 15 ° with the horizontal is short of the target by 10 m . If projected with an angle of 45 ° is away from the target by 15 m , then the angle of projection to hit the target is

Question

A particle aimed at a target, projected with an angle 15 ° with the horizontal is short of the target by 10 m . If projected with an angle of 45 ° is away from the target by 15 m , then the angle of projection to hit the target is, 1 2 sin - 1 ⁡ 1 10, 1 2 sin - 1 ⁡ 3 10, 1 2 sin - 1 ⁡ 9 10, 1 2 sin - 1 ⁡ 7 10

MARKS App · Accepted Answer

R 1 = R - 10 R 2 = R + 15 R - 10 R + 15 = sin ⁡ 2 θ 1 sin ⁡ 2 θ 2 = sin ⁡ 30 o sin ⁡ 90 o = 1 2 2 R - 20 = R + 15 R = 35 R m a x = u 2 g R = u 2 sin ⁡ 2 θ g 50 = u 2 g 35 = 50 g × sin ⁡ 2 θ g u 2 = 50 g sin ⁡ 2 θ = 35 50 = 7 10 2 θ = sin - 1 ⁡ 7 10 θ = 1 2 sin - 1 ⁡ 7 10

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