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A particle at the end of a spring executes simple harmonic motion with a period $t_1$, while the corresponding period for another spring is $t_2$. If the period of oscillation with the two springs in series is $\mathrm{t}$, then
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The correct answer is:
$\propto \mathrm{x}^2$
$\propto \mathrm{x}^2$
$t_1^2+t_2^2=T^2$
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