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A particle covers a distance from $A$ to $B$ over a period of time; the distance versus time plot is the shown below. Then which of the following is true for the motion of the particle?
Options:
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Verified Answer
The correct answer is:
Average speed is always non-zero but instantaneous speed can be zero.
The distance versus time plot for movement of a particle from $A$ and $B$ is shown in the diagram.
From graph, it is a slope of distance-time graph for position $A$ to $C$ and $D$ to $B$ is always positive, therefore both the average speed and instantaneous speed are not always zero, therefore, option (1) is not correct.
$$
\text { Average velocity }=\frac{\text { Total displacement from A to B }}{\text { Total time interval }}
$$
Since, total displacement depends on straight distance between initial and final points, hence, displacement between $A$ to $B$ always non zero, therefore the average speed is always non zero. Since, no distance is travelled between point $C$ to $D$ is zero. Hence, instantaneous speed at every instant between $C$ to $D$ is zero.
Hence, option (2) is correct and option (3) and (4) are incorrect.
From graph, it is a slope of distance-time graph for position $A$ to $C$ and $D$ to $B$ is always positive, therefore both the average speed and instantaneous speed are not always zero, therefore, option (1) is not correct.
$$
\text { Average velocity }=\frac{\text { Total displacement from A to B }}{\text { Total time interval }}
$$
Since, total displacement depends on straight distance between initial and final points, hence, displacement between $A$ to $B$ always non zero, therefore the average speed is always non zero. Since, no distance is travelled between point $C$ to $D$ is zero. Hence, instantaneous speed at every instant between $C$ to $D$ is zero.
Hence, option (2) is correct and option (3) and (4) are incorrect.
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