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A particle covers half of its total distance with speed $v_1$ and the rest half distance with speed $v_2$. Its average speed during the complete journey is
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Verified Answer
The correct answer is:
$\frac{2 y_1 y_2}{y_1+y_2}$
Velocity $y=\frac{s}{t} \Rightarrow s=v t$ The average speed of particle
$$
\begin{aligned}
& y_{\mathrm{av}}=\frac{s+s}{\frac{s}{y_1}+\frac{s}{y_2}} \\
& y_{\mathrm{av}}=\frac{2 y_1 y_2}{y_1+y_2}
\end{aligned}
$$
$$
\begin{aligned}
& y_{\mathrm{av}}=\frac{s+s}{\frac{s}{y_1}+\frac{s}{y_2}} \\
& y_{\mathrm{av}}=\frac{2 y_1 y_2}{y_1+y_2}
\end{aligned}
$$
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