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A particle executes simple harmonic motion along a straight line with an amplitude $A$. The potential energy is maximum when the displacement is
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$\pm A$
P.E. $=\frac{1}{2} m \omega^2 x^2$
It is clear P.E. will be maximum when $x$ will be maximum i.e., at $x= \pm A$
It is clear P.E. will be maximum when $x$ will be maximum i.e., at $x= \pm A$
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