A particle executes simple harmonic motion and it is located at x = a , b and c at time t 0 , 2 t 0 a n d 3 t 0 respectively. The frequency of the oscillation is:

Question

A particle executes simple harmonic motion and it is located at x = a , b and c at time t 0 , 2 t 0 a n d 3 t 0 respectively. The frequency of the oscillation is:, 1 2 π t 0 cos - 1 ⁡ a + c 2 b, 1 2 π t 0 cos - 1 ⁡ a + 2 b 3 c, 1 2 π t 0 cos - 1 ⁡ a + b 2 c, 1 2 π t 0 cos - 1 ⁡ 2 a + 3 c b

MARKS App · Accepted Answer

a = A sin ⁡ ω t 0 b = A sin ⁡ 2 ω t 0 c = A sin ⁡ 3 ω t 0 a + c = A sin ⁡ ω t 0 + sin ⁡ 3 ω t 0 = 2 A sin ⁡ 2 ω t 0 cos ⁡ ω t 0 ∵ sin C + sin D = 2 sin C + D 2 cos C − D 2 ω = 1 t 0 cos - 1 ⁡ a + c 2 b ⇒ f = 1 2 π t 0 cos - 1 ⁡ a + c 2 b

Search any question & find its solution

Looking for more such questions to practice?