A particle executes simple harmonic motion between x = - A and x = + A . If it takes a time T 1 to g 0 from x = 0 to x = A / 2 and T 2 to go from x = A / 2 to x = A . Then

Question

A particle executes simple harmonic motion between x = - A and x = + A . If it takes a time T 1 to g 0 from x = 0 to x = A / 2 and T 2 to go from x = A / 2 to x = A . Then, T 1 T 2, T 1 > T 2, T 1 = T 2, T 1 = 2 T 2

MARKS App · Accepted Answer

Equation of SHM x = a sin ω t at x = 0 ; t o = 0 at x = A 2 f r o m e q u a t i o n A 2 = a sin 2 π T t 1 ⇒ t 1 = T 12 at x = A from equation A = a sin 2 π T t 1 ⇒ t 1 = T 4 so time from x = 0 t o x = A 2 T 1 = t 1 - t o = T 12 and time from x = A 2 t o x = A T 2 = t 2 - t 1 = T 4 - T 12 = T 6 so T 1 T 2

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