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Question: Answered & Verified by Expert
A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, velocity of the particle is 10 cm s-1. The distance of the particle from the mean position when its speed becomes 5 cm s-1 is α cm, where α=______.
PhysicsOscillationsJEE MainJEE Main 2024 (27 Jan Shift 1)
Solution:
2184 Upvotes Verified Answer
The correct answer is: 12

The formula to calculate the velocity of the particle at the mean position is given by

V=Aω   ...1

From equation (1), it follows that

10=4×ωω=52 rad s-1

The formula to calculate the velocity of the particle at any instantaneous position x can be expressed as

v=ωA2-x2   ...2

From equation (2), it follows that

5=5242-x2x2=16-4=12x=12 cm

Hence, α=12.

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