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Question: Answered & Verified by Expert
A particle executes simple harmonic motion with an amplitude of 5 cm . When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is:
PhysicsOscillationsJEE MainJEE Main 2019 (10 Jan Shift 2)
Options:
  • A 8π3
  • B 38π
  • C 4π3
  • D 73π
Solution:
2743 Upvotes Verified Answer
The correct answer is: 8π3
v=ω52-42=3ω

a=ω2×4

a=v

4ω2=3ω

ω=34=2πT

T=8π3 sec

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