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Question: Answered & Verified by Expert
A particle executes simple harmonic oscillation with an amplitude A. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
PhysicsOscillationsNEET
Options:
  • A T / 8
  • B T / 12
  • C T / 2
  • D T / 4
Solution:
2746 Upvotes Verified Answer
The correct answer is: T / 12
Using the equation of SHM,
x t = A  sin ω t (from the equilibruim position)

At x t = A / 2

A 2 = A  sin  ω t

sin π 6 = sin ω t or, π 6 = 2 π t T ω = 2 π T

or,  t = T / 12 .

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