A particle executing SHM has a maximum speed of 0.5 m s - 1 and a maximum acceleration of 1.0 m s - 2 . The angular frequency of oscillation is

Question

A particle executing SHM has a maximum speed of 0.5 m s - 1 and a maximum acceleration of 1.0 m s - 2 . The angular frequency of oscillation is, 2 rad s - 1, 0.5 rad s - 1, 2 π rad s - 1, 0 .5 π rad s - 1

MARKS App · Accepted Answer

In SHM, Maximum velocity v m a x = ω A Maximum acceleration a m a x = A ω 2 ⇒ ω = A ω 2 A ω = a m a x v m a x v m a x = 0.5 m s - 1 a m a x = 1.0 m s - 1 ω = 1 0.5 = 10 5 = 2 rad s - 1

Search any question & find its solution

Looking for more such questions to practice?