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A particle executing simple harmonic motion of amplitude $5$ cm has maximum speed of $31.4 \mathrm{~cm} / \mathrm{s}$. The frequency of its oscillation is
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1 Hz
Maximum speed of a particle executing SHM is $u_{\max }=a \omega=a(2 \pi n)$
$\Rightarrow n=\frac{u_{\max }}{2 \pi a}$
Here, $u_{\max }=31.4 \mathrm{~cm} / \mathrm{s}, a=5 \mathrm{~cm}$
Substituting the given values, we have
$n=\frac{31.4}{2 \times 3.14 \times 5}=1 \mathrm{~Hz}$
$\Rightarrow n=\frac{u_{\max }}{2 \pi a}$
Here, $u_{\max }=31.4 \mathrm{~cm} / \mathrm{s}, a=5 \mathrm{~cm}$
Substituting the given values, we have
$n=\frac{31.4}{2 \times 3.14 \times 5}=1 \mathrm{~Hz}$
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