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A particle has displacement of $12 \mathrm{~m}$ towards east and $5 \mathrm{~m}$ towards north then $6 \mathrm{~m}$ vertically upward. The sum of these displacements is
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$14 .31 \mathrm{~m}$
$R=\sqrt{12^2+5^2+6^2}=\sqrt{144+25+36}=\sqrt{205}=14.31 \mathrm{~m}$
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