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A particle has simple harmonic motion. The equation of its motion is $\mathrm{x}=5 \sin (4 t-\pi / 6)$, where $\mathrm{x}$ is its displacement. If the displacement of the particle is 3 units, then its velocity is
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16 units
From the given equation,
The amplitude of the wave is $\mathrm{a}=5$ and the angular velocity of the wave is $\omega=4$
The velocity of the wave can be obtained as: $\therefore \mathrm{v}=\omega \sqrt{\mathrm{a}^2-\mathrm{y}^2}$ $=4 \sqrt{(5)^2-(3)^2}=16$ units
The amplitude of the wave is $\mathrm{a}=5$ and the angular velocity of the wave is $\omega=4$
The velocity of the wave can be obtained as: $\therefore \mathrm{v}=\omega \sqrt{\mathrm{a}^2-\mathrm{y}^2}$ $=4 \sqrt{(5)^2-(3)^2}=16$ units
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