A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β . Then, its time period of vibration will be:

Question

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β . Then, its time period of vibration will be:, α β, β 2 α, 2 π β α, β 2 α 2

MARKS App · Accepted Answer

ω 2 A = α ω A = β ⇒ ω = α β ⇒ T = 2 π ω = 2 π β α

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