A particle is executing S. H. M. of periodic time $ T $. The time taken by a particle in moving from mean position to half the maximum displacement is $ \left(\sin 30^{\circ}=0.5\right) $

Question

A particle is executing S. H. M. of periodic time $ T $. The time taken by a particle in moving from mean position to half the maximum displacement is $ \left(\sin 30^{\circ}=0.5\right) $, $ \frac{T}{2} $, $ \frac{T}{4} $, $ \frac{\frac{r}{s}}{\frac{1}{s}} $, $ \frac{T}{12} $

MARKS App · Accepted Answer

The equation of displacement of SHM in terms of amplitude and angular frequency is x = A sin ω t Here equation is given, x = A 2 ⇒ A 2 = A sin ω t ⇒ ω t = π 6 ⇒ 2 π T t = π 6 ⇒ t = T 12

Search any question & find its solution

Looking for more such questions to practice?