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Question: Answered & Verified by Expert
A particle is given a horizontal velocity u, from the point P on a smooth horizontal floor which has a vertical circular track at the end. ABC is a semicircular track of radius r in the vertical plane. If the path length PA is x=3r and the particle returns to point P, then the initial speed of the particle is

PhysicsLaws of MotionJEE Main
Options:
  • A u=5gr
  • B u=52gr
  • C u=4gr
  • D u=32gr
Solution:
2268 Upvotes Verified Answer
The correct answer is: u=52gr
vC2=u2-2g×2r

vC2=u2-4gr  1

x=vC4rg  2




or, x2=vC24rg

as, x=3r

 9r2=vC24rg

vC2=94 gr

From equation (1) u2-4gr=94gr

u2=254gr or u=52gr

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