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A particle is moving along a circular path with constant speed and centripetal acceleration $a$. If the speed is doubled, the ratio of its acceleration after and before the change is
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Verified Answer
The correct answer is:
4:1
$\begin{aligned}
& \text { Centripetal acceleration }=\frac{v^2}{R} \\
& \therefore a \propto v^2
\end{aligned}$
If the speed is doubled, then the ratio of its acceleration after and before are in $4: 1$ ratio.
& \text { Centripetal acceleration }=\frac{v^2}{R} \\
& \therefore a \propto v^2
\end{aligned}$
If the speed is doubled, then the ratio of its acceleration after and before are in $4: 1$ ratio.
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