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A particle is moving in a circle of radius 'R' with constant speed 'V'. The magnitude of average acceleration after half revolution is
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Verified Answer
The correct answer is:
$\frac{2 V^{2}}{\pi R}$
Change in speed after half revolution is $2 \mathrm{~V}$
$$
\begin{aligned}
\quad & \text { Time taken }=\frac{\pi R}{V} \\
\therefore \quad \text { average speed } &=\frac{2 V^{2}}{\pi R}
\end{aligned}
$$
$$
\begin{aligned}
\quad & \text { Time taken }=\frac{\pi R}{V} \\
\therefore \quad \text { average speed } &=\frac{2 V^{2}}{\pi R}
\end{aligned}
$$
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