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Question: Answered & Verified by Expert
A particle is moving in a circle of radius 'R' with constant speed 'V'. The magnitude of average acceleration after half revolution is
PhysicsMotion In Two DimensionsMHT CETMHT CET 2020 (16 Oct Shift 1)
Options:
  • A $\frac{2 V^{2}}{\pi R}$
  • B $\frac{2 \pi}{R V^{2}}$
  • C $\frac{2 \mathrm{~V}}{\pi \mathrm{R}^{2}}$
  • D $\frac{2 R}{\pi V}$
Solution:
2755 Upvotes Verified Answer
The correct answer is: $\frac{2 V^{2}}{\pi R}$
Change in speed after half revolution is $2 \mathrm{~V}$
$$
\begin{aligned}
\quad & \text { Time taken }=\frac{\pi R}{V} \\
\therefore \quad \text { average speed } &=\frac{2 V^{2}}{\pi R}
\end{aligned}
$$

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