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A particle is moving in a circle with uniform speed ' $v$ '. In moving from a point to another diametrically opposite point
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Verified Answer
The correct answer is:
the momentum changes by $2 \mathrm{mv}$
At both points, the momentum will be mv, but will be in opposite directions.
$$
\begin{array}{ll}
\therefore & \Delta \mathrm{P}=\mathrm{mv}-(-\mathrm{mv}) \\
\therefore & \Delta \mathrm{P}=2 \mathrm{mv}
\end{array}
$$
The momentum changes by $2 \mathrm{mv}$.
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