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Question: Answered & Verified by Expert
A particle is moving in xy-plane with a constant speed v0 such that its y displacement is given by y=αe-2vx3v0, where vx is component of velocity along the x-axis. If at some instant x component of it velocity is positive and the slope of the tangent on its path is -13, then the displacement of the particle in y-direction at the instant is
PhysicsMotion In Two DimensionsJEE Main
Options:
  • A α e - 1
  • B α e - 2
  • C Zero
  • D α 2 e
Solution:
1736 Upvotes Verified Answer
The correct answer is: α e - 1
Here, particle is moving in two - dimensional (x – y) plane, with constant speed so slope of

graph d y d x = v y v x  and  v 0 = v x 2 + v y 2 .

As slope,  dy dx = - 1 3 = v y v x

So,          v x = - v y 3

On squaring and adding

v x 2 + v y 2 = v 0 2

3 v y 2 + v y 2 = v 0 2

v y = ± v 0 2

v x = 3 v 0 2

So,           y = α e - 2 3 v 0 × 3 v 0 2

y = α e - 1

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