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Question: Answered & Verified by Expert
A particle is moving such that its position coordinates x, y are 2 m, 3 m at time t=0, 6 m, 7 m at time t=2 s and 13 m, 14 m at time t=5 s. The average velocity vector Vav from t=0 to t=5 s is:
PhysicsMotion In One DimensionNEETNEET 2014
Options:
  • A 1513i^+14j^
  • B 73i^+j^
  • C 2i^+j^
  • D 115i^+j^
Solution:
1051 Upvotes Verified Answer
The correct answer is: 115i^+j^

The position vector of the particle at time t=0 is ri=2i^+3j^
The position vector of the particle at time t=5 s is rf=13i^+14j^
The displacement of the particle is s=11i^+11j^
The average velocity vector V=11i^+11j^5

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