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Question: Answered & Verified by Expert
A particle is performing S.H.M. with maximum velocity ' $\mathrm{v}$ '. If the amplitude is tripled and periodic time is doubled then maximum velocity will be
PhysicsOscillationsMHT CETMHT CET 2021 (21 Sep Shift 2)
Options:
  • A $1.5 \mathrm{v}$
  • B $3 \mathrm{v}$
  • C $2 \mathrm{v}$
  • D $\mathrm{v}$
Solution:
2452 Upvotes Verified Answer
The correct answer is: $1.5 \mathrm{v}$
$$
\mathrm{V}=\mathrm{V}_{\max }=\omega \mathrm{A}=\frac{2 \pi}{\mathrm{T}} \cdot \mathrm{A}
$$
If $\mathrm{A}$ is tripled and $\mathrm{T}$ is doubled, $\mathrm{V}_{\max }$ will become $\frac{3}{2}$ times or 1.5 times.

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