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A particle is performing U.C.M. along the circumference of circle of diameter $50 \mathrm{~cm}$ with frequency $2 \mathrm{~Hz}$. The acceleration of the particle in $\mathrm{m} / \mathrm{s}^2$ is
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$4 \pi^2$
$\begin{aligned} & \mathrm{d}=50 \mathrm{~cm} \\ & \therefore \mathrm{r}=25 \times 10^{-2} \mathrm{~m}, \mathrm{f}=2 \mathrm{~Hz} \\ & \mathrm{a}=\mathrm{r} \omega^2=4 \pi^2 \mathrm{f}^2 \mathrm{r}=4 \pi^2 \times 4 \times 25 \times 10^{-2}=4 \pi^2\end{aligned}$
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