A particle is projected at an angle of 60 ° above the horizontal with a speed of 10 m s - 1 . After some time the direction of its velocity makes an angle of 30 ° above the horizontal. The speed of the particle at this instant is

Question

A particle is projected at an angle of 60 ° above the horizontal with a speed of 10 m s - 1 . After some time the direction of its velocity makes an angle of 30 ° above the horizontal. The speed of the particle at this instant is, 5 3 m s - 1, 5 3 m s - 1, 5 m s - 1, 10 3 m s - 1

MARKS App · Accepted Answer

Let v be the velocity of projectile at this instant. Horizontal component of velocity remains unchanged. Therefore, vcos 30 ° = 10 cos 60 ° v 3 2 = 10 2 ∴ v = 10 3 m s - 1

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