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Question: Answered & Verified by Expert
A particle is projected from the earth's surface with a velocity of 50 m s-1 at an angle θ with the horizontal. After 2 s it just clears a wall 5 m high. What is the value of 55 sinθ? (g=10 m s-2)
PhysicsMotion In Two DimensionsJEE Main
Solution:
1495 Upvotes Verified Answer
The correct answer is: 13.75



Using equation of motion in y-dir s=ut+12at2

Height after 2 s,

h=5=50 sinθt-12gt2

5 = 50 sin θ 2 - 1 2 · 10 · 2 2

25 100 = sin θ

sin θ = 1 4

55 sinθ=554=13.75

 

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