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Question: Answered & Verified by Expert
A particle is projected from the ground with an initial speed of $v$ at an angle $\theta$ with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is
PhysicsMotion In Two DimensionsAIIMSAIIMS 2018 (26 May)
Options:
  • A $\frac{v}{2} \sqrt{1+2 \cos ^2 \theta}$
  • B $\frac{v}{2} \sqrt{1+\cos ^2 \theta}$
  • C $\frac{v}{2} \sqrt{1+3 \cos ^2 \theta}$
  • D $v \cos \theta$
Solution:
2526 Upvotes Verified Answer
The correct answer is: $\frac{v}{2} \sqrt{1+3 \cos ^2 \theta}$
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