A particle is projected from the surface of the earth with a velocity of 5 ms - 1 at an angle θ with the horizontal. Another particle is projected on the surface of some other planet with a velocity of 3 ms - 1 at the same angle and it follows a trajectory which is identical to the trajectory of the projectile which is fired on earth. The value of the acceleration due to gravity on that planet is [given that the acceleration due to gravity on the surface of earth, g = 9 . 8 ms - 2 ]

Question

A particle is projected from the surface of the earth with a velocity of 5 ms - 1 at an angle θ with the horizontal. Another particle is projected on the surface of some other planet with a velocity of 3 ms - 1 at the same angle and it follows a trajectory which is identical to the trajectory of the projectile which is fired on earth. The value of the acceleration due to gravity on that planet is [given that the acceleration due to gravity on the surface of earth, g = 9 . 8 ms - 2 ], 16 . 3 ms - 2, 1 . 8 ms - 2, 3 . 5 ms - 2, 5 . 9 ms - 2

MARKS App · Accepted Answer

y = x tan θ - gx 2 2 u 2 cos 2 θ For equal trajectories for same angle of projection g u 2 = constant ⇒ 9 . 8 5 2 = g 3 2 g ' = 9 . 8 × 9 25 = 3 . 528 m / s 2 = 3 . 5 m / s 2

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