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A particle is projected in air at some angle to the horizontal, moves along parabola as shown in figure where $x$ and $y$ indicate horizontal and vertical directions, respectively. Shown in the diagram, direction of velocity and acceleration at points $A, B$ and $C$.
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According to given diagram in which a particle is projected at an angle $\theta$
and path of projectile is always parabola.
If point $B$ is at its maximum height of trajectory so vertical component of velocity at $B, v_y=0$ and horizontal component of velocity $v_x=u \cos \theta=$ constant.
Velocity will always be tangential to the curve in the direction of motion so velocities at points $A, B$, and $C$ are tangent and acceleration is always vertically downward equal to acceleration due to gravity $(g)$.
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